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2. We shall now inquire what are the relations of the conic section to the triangle of reference, when certain rela- · tions exist among the coefficients of the equation.

First, suppose u, v, w, all = 0.

The equation then assumes the form

u'ẞy + v'ya+w'aß = 0,

which we shall write

λβγ + μγα + ναβ = 0.

Now, if in this equation we put a = 0, it reduces itself to λβγ = 0,

which requires either that = 0, or that y=0.

It hence appears that the curve passes through two of the angular points (B, C) of the triangle of reference. It may similarly be shewn to pass through the third. Hence the equation

λβγ + μγα + ναβ = 0,

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represents a conic, described about the triangle of reference.

3. Let us now inquire how the line

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β

If in the equation of the conic we put +

μ

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which is the same thing, μy + vẞ= 0, it reduces to λBy = 0.

Hence the line +2=0 meets the conic in the points in

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B Y
μ

ע

which it meets the lines ẞ=0, y=0; but these two points coincide, since the line in question evidently passes through the point of intersection of B=0 and y=0. Hence the straight line and the conic meet one another in coincident points, that is, they touch one another at the point A.

Similarly, the equations of the tangents at B and C are

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4. To determine the position of the centre of the conic.

Through the angular points A, B, C of the triangle of reference draw the tangents EAF, FBD, DCE. Bisect

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AC, AB respectively in H, I, join EH, FI, and produce them to intersect in O. Then, since every straight line drawn through the intersection of two tangents so as to bisect their chord of contact passes also through the centre, O will be the centre of the conic.

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μ

γ

ע

or

- λα +μό + vc λα - μό + ve λα + μό - vc

These equations determine the position of the centre.

COR. We may hence deduce the relation which must hold between λ, u, v, in order that the conic may be a parabola. For, since the centre of a parabola is at an infinite distance, its co-ordinates will satisfy the equation

aa+bB+cy = 0.

We hence obtain the following equation:

X3u2 + μ3b2 + v3c2 - 2μv bc - 2vλca — 2λμ ab = 0,

which is equivalent to

± (λa)* ± (μb)* ± (vc)* = 0,

as the necessary and sufficient condition that the conic should be a parabola.

5. To determine the condition that a given straight line may touch the conic.

If the conic be touched by the straight line (7, m, n), the two values of the ratio By, obtained by eliminating a between the equations

λβγ + μγα + ναβ = 0,

la+mß + ny = 0,

must be coincident. The equation which determines these is

− xlBy + (μy+vß) (mß+ny) = 0,

and the condition that the two values of By be equal, is

4μn.vm — (μm + vn — X7)2 = 0,

or λ2l2 + μ3m2 + v3n2 — 2 μv. mn — 2vλ.nl — 2λμ. lm = 0,

which is equivalent to

± (~7)* ± (μm)* ± (vn)3 = 0,

If this be compared with the condition investigated in Art. (4) that the conic may be a parabola, it will be observed that the parabola satisfies the analytical condition of touching the straight line aa+b+cy=0. This is generally expressed by saying that every parabola touches the line at infinity.

6. To investigate the equation of the circle, circumscribing the triangle of reference.

This may be deduced from the consideration that the co-ordinates of the centre of the circumscribing circle are respectively proportional to cos A, cos B, cos C (see p. 4). Or

it may be independently investigated as follows. Draw EAF, FAD, DAE (fig. 2), tangents to the circle, then the angle EAC is equal to ABC, and FAB to_ACB (Euc. III. 32). Hence the equation of the tangent EAF must be

are

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Similarly the equations of the other tangents FBD, DCE

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